Media Summary: This video is part of a lecture series available at ERRATUM - At :18, the computation for utilisation factor would be (1car/6mins) / (1car/10mins) = 5/3 or 1.6667. This is a聽...
This video is part of a lecture series available at ERRATUM - At :18, the computation for utilisation factor would be (1car/6mins) / (1car/10mins) = 5/3 or 1.6667. This is a聽...
Dear students this is the eighth
Problem
Ladies and gentlemen these are the
for more
This video is part of a lecture series available at https://www.youtube.com/channel/UCMvO2umWRQtlUeoibC8fp8Q.
So before we discuss the
All the length of the
Simple traffic
BUS370_Queueing.
Explained and solved
ERRATUM - At @12:18, the computation for utilisation factor would be (1car/6mins) / (1car/10mins) = 5/3 or 1.6667. This is a聽...
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